Given two binary trees, write a function to check if they are equal or not.
Two binary trees are considered equal if they are structurally identical and the nodes have the same value.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isSameTree(TreeNode p, TreeNode q) {
if(p == null && q == null){
return true;
} else if(p == null || q == null){
return false;
} else {
if(p.left == null && q.left == null){
if(p.right == null && q.right == null){
if(p.val == q.val){
return true;
} else {
return false;
}
} else if(p.right == null || q.right == null){
return false;
} else {
if(p.val == q.val){
if(isSameTree(p.right, q.right)){
return true;
} else {
return false;
}
} else {
return false;
}
}
} else if(p.left == null || q.left ==null){
return false;
} else {
if(p.val == q.val){
if(isSameTree(p.left, q.left) && isSameTree(p.right, q.right)){
return true;
} else {
return false;
}
} else {
return false;
}
}
}
}
}
consider carefully and attentively, care about all corner cases. Every note's value, left child and right child should be compare completely
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